(6x^-3y^5/36x^2y^-7)^-2

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Solution for (6x^-3y^5/36x^2y^-7)^-2 equation: 


D( x )

x = 0

x^2*((6*x^-3*y^5)/36)*y^-7 = 0

x = 0

x = 0

x^2*((6*x^-3*y^5)/36)*y^-7 = 0

x^2*((6*x^-3*y^5)/36)*y^-7 = 0

1/6*x^-1*y^-2 = 0 // : 1/6*y^-2

x^-1 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

(x^2*((6*x^-3*y^5)/36)*y^-7)^-2 = 0

36*x^2*y^4 = 0 // : 36*y^4

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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